solved @hanky 웃 panky!
i implementing login function.
the javascript part:
function login() { var n = $('#userl').val(); var p = $('#passl').val(); if ( n != "" && p != ""){ $.post("functions.php",{userl: n, passl: p}).done(function(mesaj){ if(mesaj == "") alert("!!!!!!!!!!empty string!!!!!"); else alert(mesaj); }); } else { alert("enter name and/or passwort"); } }; and function function.php looks:
function login($nume,$parola) { $sql = "select id `users` nume ='".$nume."' password = '".md5($parola)."'"; $q = mysql_query($sql); if(!$q) die(json_encode(array("mesaj" => "invalid"))); else{ $x = mysql_fetch_array($q); if (empty($x)) die(json_encode(array('mesaj' => 'the user not exist'))); else { // $user = new user($x['id']); session_start(); $_session['user_id'] = $x['id']; $_session['loggedin'] = "yes"; die(json_encode(array("mesaj"=>"you logged"))); } } //this part may useless die(json_encode(array("mesaj"=>"you not logged"))); } if (isset($_post['nume']) , isset($_post['parola'])) login($_post['nume'], $_post['parola']); the problem keeps alerting empty string , think doesn'n acccess login function php...so message comes way went: empty
$.post("functions.php",{userl: n, passl: p}) compare with
if (isset($_post['nume']) , isset($_post['parola'])) and spot error :)
you sending user1 , pass1 , in php checking nume , parola don't exist obviously.
